Lecture 12: Continuity of functions
Postgraduate Entrance Exam Mathematics Study Notes: Lecture 12: Continuity of Functions. Retain original formulas, diagrams, and example problems.
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12.1 Assessment Content
- Content
- 1. The concept of continuity;
- 2. Breaks and their classification;
- 3. Operations and properties of continuity;
- 4. Properties of continuous functions on closed intervals;
- Question type
- Question Type 1: Discuss the types of function continuity and discontinuity;
- Problem Type 2: Proof problems with properties of continuous functions on closed intervals;
12.2 The Concept of Continuity
#####Definition: Continuity
description:
Definition 1: $y=f(x)$ is continuous at $x_0$ if $\lim_{\Delta x\to0}[f(x_0+\Delta x)-f(x_0)]=0$.
Definition 2: $y=f(x)$ is continuous at $x_0$ if $\lim_{x\to x_0}f(x)=f(x_0)$.
Explanation
- Equivalent form: $y=f(x)$ is continuous at $x_0$ iff $\lim_{x\to x_0}f(x)=f(x_0)$.
- Left and right continuous:
- 1. Left continuous: $\lim_{x\to x^-_0}f(x)=f(x_0)$
- 2. Right continuous: $\lim_{x\to x^+_0}f(x)=f(x_0)$
- $f(x)$ Sufficient and necessary conditions for continuity: $f(x)$Left continuous and right continuous,left and right continuous are equal;
Inner and Outer Continuities
- Inner continuous: every point in $(a,b)$ is continuous;
- Outer continuous: Every point in $[a,b]$ is continuous, and point a is continuous to the right and point b to the left;
Continuous within the range
- A function is continuous within an interval = all points on the interval are continuous =The left and right limits of all points exist and are equal, and the function value equals this point;
Question Type: Discussthecontinuityoffunctionsandtypesofdiscontinuities
PART 1: Problem-solving methods
- When discussing the continuity of functions, it is necessary to clearly describe which points are discontinuous and why they are continuous on other intervals;
PART 2: Typical Example Problems
Example Problem: $\text{ Known }f(x)=\begin{cases}(\cos x)^{1/x^2},x\neq0,\\a,&x=0&\end{cases}$, then continue at x=0, then find a;
- Analysis
- Because it is continuous at x=0, the limit value of this point exists and is equal;
- Analysis
- $\lim_{x\to0}f(x)=\lim_{x\to0}(nx)^{\frac12}=\lim_{x\to0}[1+(ax-1)]^{\frac1{x^2}}=e^{-\frac12}=f(0)=0,$
- Question Type: #
Example Question: $f(x)=\lim_{n\to\infty}\frac{1+x}{1+x^{{2n}}}$, discuss the breakpoint of the function;
- Analysis
- Analysis
- First, segment it to get: $f(x)=\begin{cases}1+x&|x|<1\\0&|x|>1\\1&x=1\\0&x=-1\end{cases}$
- 0 points continuous, 1 point discontinuous;
- Therefore: there exists a discontinuity point x=1;
- Question Type: #