Lecture 18: Equivalent Systems of Linear Equations
Graduate Entrance Examination Mathematics study notes: Lecture 18: Equivalent Systems of Linear Equations. Original formulas, diagrams, and examples are retained.
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18.1 Basic Concepts
#####Definition: Solvethesystemofequationstogether
Description: systems $A_{mn}x=0$ and $B_{sn}x=0$ have exactly the same solutions, they are called homosolvable systems;
Thus: Ax=0,Bx=0 is a system of homosolvable equations;
Explanation
- Meaning:
- Proof
r(A)<r(B)->using sets of vectors; - Proof
r(A)=r(B)->Use a system of equations to prove->is the same solution; - Concept:
- Solution substitution:
- The solution of
Ax=0satisfiesBx=0, and the solution ofBx=0satisfiesAx=0(simply substitute the solution into each other to get the result) - Method:
r(A)=r(B), and the solution ofAx=0satisfiesBx=0(or the solution ofBx=0satisfiesAx=0)- Sanji is the same:
- $r\left(A\right)=r\left(B\right)=r\left(\left[\begin{matrix}A\\\\B\end{matrix}\right]\right)$
- Explanation:
Ax=0andBx=0are the same<->The equivalence of two sets of vectors is: $\xi_1,\xi_2,\cdots,\xi_s=\eta_{1},\eta_{2}\cdots\eta_{s}$<->$r(\xi_1,\xi_2,\cdots,\xi_s)=r(\eta_{1},\eta_{2}\cdots\eta_{s})$ and the first set of vectors can be represented linearly by the second set;<->r(A)=r(B)=r(A|B)<->r(A)=r(B)and the solution ofAx=0is a solution ofBx=0;<->$r\left(A\right)=r\left(B\right)=r\left(\left[\begin{matrix}A\\\\B\end{matrix}\right]\right)$- Conclusion:
- $r(AA^{T})=r(A^{T})=r(A)=r(A^{T}A)$